sin^2xcos^2x=1-cos4x/8

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Solution for sin^2xcos^2x=1-cos4x/8 equation: 


Oblicz to!

15-(5/12) = 0

(7*x^1*e^x)/2

(6*x^2)/3 = N

x/(-0.8) = 8.48

5*((x^2)/2)-(5*x)-1.5 = 0

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